/*
Though leaves are many , the root is one.
Through all the lying days of my youth
I swayed my leaves and flowers in the sun.
Now I may wither into the truth.
	  	  	- William Butler Yeats
*/
//#pragma GCC optimize("Ofast,no-stack-protector")
//#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx")
//#pragma GCC target("avx,tune=native")
#include<bits/stdc++.h>
#pragma comment("-Wl,--stack=1024000000")
//#include<ext/pb_ds/assoc_container.hpp>
using namespace std;
//using namespace __gnu_pbds;
const int inf=0x3f3f3f3f;
const double eps=1e-6;
const int mod=1000000007;
typedef long long ll;
#ifndef LOCAL
#define cerr if(0)cout
#define eprintf(...) 0
#else
#define eprintf(...) fprintf(stderr, __VA_ARGS__)
#endif
inline string getstr(string &s,int l,int r){string ret="";for(int i=l;i<=r;i++)ret.push_back(s[i]);return ret;}
int modpow(int x,int y,int md=mod){int ret=1;do{if(y&1)ret=(ll)ret*x%md;x=(ll)x*x%md;}while(y>>=1);return ret;}
inline int Rand(){return rand()*32768+rand();}
int n,k,a[100005],ans;
vector<int>g[100005];
int dfs(int x,int par){
	int mx=0;
	for(auto to:g[x]){
		mx=max(dfs(to,x),mx);
	}
	if(mx==k-1&&a[x]!=1)ans++;
	return (mx+1)%k;
}
int main(){
	cin>>n>>k;
	for(int i=1;i<=n;i++)cin>>a[i];
	for(int i=2;i<=n;i++){
		g[a[i]].push_back(i);
	}
	if(a[1]!=1)ans++,a[1]=1;
	dfs(1,-1);
	cout<<ans<<endl;
	return 0;
}
#include <iostream>
#include <iomanip>
#include <string>
#include <stack>
#include <vector>
#include <complex>
#include <math.h>
#include <stdio.h>
#include <algorithm>
#include <utility>
#include <functional>
#include <iterator>
#include <map>
#include <set>
#include <queue>
#include <list>
#include <regex>
#include <limits>
#include <time.h>
#include <cstdint>
using namespace std;
using pii  = pair<int,int>;
using ll=long long;
using ld=long double;
#define pb push_back
#define mp make_pair
#define sc second
#define fr first
#define stpr setprecision
#define cYES cout<<"YES"<<endl
#define cNO cout<<"NO"<<endl
#define cYes cout<<"Yes"<<endl
#define cNo cout<<"No"<<endl
#define rep(i,n) for(ll i=0;i<(n);++i)
#define Rep(i,a,b) for(ll i=(a);i<(b);++i)
#define rrep(i,n) for(ll i=n-1;i>=0;i--)
#define rRep(i,a,b) for(ll i=a;i>=b;i--)
#define crep(i) for(char i='a';i<='z';++i)
#define psortsecond(A,N) sort(A,A+N,[](const pii &a, const pii &b){return a.second<b.second;});
#define ALL(x) (x).begin(),(x).end()
#define debug(v) cout<<#v<<":";for(auto x:v){cout<<x<<' ';}cout<<endl;
#define endl '\n'
int ctoi(const char c){
  if('0' <= c && c <= '9') return (c-'0');
  return -1;
}
ll gcd(ll a,ll b){return (b == 0 ? a : gcd(b, a%b));}
ll lcm(ll a,ll b){return a*b/gcd(a,b);}
constexpr ll MOD=1000000007;
constexpr ll INF=1000000011;
constexpr ll MOD2=998244353;
constexpr ll LINF = 1001002003004005006ll;
constexpr ld EPS=10e-8;
template <class T, class U> inline bool chmax(T& lhs, const U& rhs) { if (lhs < rhs) { lhs = rhs; return 1; } return 0; }
template <class T, class U> inline bool chmin(T& lhs, const U& rhs) { if (lhs > rhs) { lhs = rhs; return 1; } return 0; }
template<typename T> istream& operator>>(istream& is,vector<T>& v){for(auto&& x:v)is >> x;return is;}
template<typename T,typename U> istream& operator>>(istream& is, pair<T,U>& p){ is >> p.first; is >> p.second; return is;}
template<typename T,typename U> ostream& operator>>(ostream& os, const pair<T,U>& p){ os << p.first << ' ' << p.second; return os;}
template<class T> ostream& operator<<(ostream& os, vector<T>& v){
  for(auto i=begin(v); i != end(v); ++i){
    if(i !=begin(v)) os << ' ';
    os << *i;
  }
  return os;
}

const int MAX = 4000003;

long long fac[MAX], finv[MAX], inv[MAX];

// テーブルを作る前処理
void COMinit() {
    fac[0] = fac[1] = 1;
    finv[0] = finv[1] = 1;
    inv[1] = 1;
    for (int i = 2; i < MAX; i++){
        fac[i] = fac[i - 1] * i % MOD;
        inv[i] = MOD - inv[MOD%i] * (MOD / i) % MOD;
        finv[i] = finv[i - 1] * inv[i] % MOD;
    }
}

// 二項係数計算
long long COM(int n, int k){
    if (n < k) return 0;
    if (n < 0 || k < 0) return 0;
    return fac[n] * (finv[k] * finv[n - k] % MOD) % MOD;
}

int main(){ 
  COMinit();
  ll N,M,K,ANS=0;
  cin >> N >> M >> K;
  ll com = COM(N*M-2,K-2);
  Rep(i,1,N){
    ll Z=1;
    Z*=M*M*(N-i);
    Z%=MOD;
    Z=(Z*com)%MOD;
    Z=(Z*i)%MOD;
    ANS=(ANS+Z)%MOD;
  }
  Rep(i,1,M){
    ll Z=1;
    Z*=N*N*(M-i);
    Z%=MOD;
    Z=(Z*com)%MOD;
    Z=(Z*i)%MOD;
    ANS=(ANS+Z)%MOD;
  }
  cout << ANS << endl;
}