#include <bits/stdc++.h>
#include <set>
#include <numeric>
#define rep(i,n) for (int i=0; i < (n); ++i)
#define all(a) a.begin(), a.end()
using ll = long long;
using namespace std;
 
// ll gcd(ll a, ll b) { return b ? gcd(b, a % b) : a; }




int minimam(int a,int b,int c, int d);

int main() {
  int a,b,c,d; cin >> a >> b >> c >> d;
  int num;
  num = minimam(a,b,c,d);
  cout << num << endl;
  return 0;
}
int minimam(int a,int b,int c, int d) {
  return min(a,b)+min(c,d);
}
#include <bits/stdc++.h>
using namespace std;
#define ll long long
#define ld long double
#define rep(i,n) for(int i = 0; i < (int)(n); i++)
#define repo(i,n) for(int i = 1; i < (int)(n); i++)
#define pb push_back
#define mp make_pair
#define np next_permutation
#define lb lower_bound
#define ub upper_bound
#define fi first
#define se second
#define all(x) (x).begin(),(x).end()
#define mod 1000000007
#define pi acos(-1.0)
const ll INF = 1LL<<61;
ll gcd(ll x, ll y) { return y ? gcd(y, x % y) : x; }
ll lcm(ll x, ll y) { return x / gcd(x, y) * y; }
ll jou(ll N, ll P){if(P==0) return 1;
  if(P%2==0){ll t = jou(N, P/2);return t*t % mod;
  }return (N * jou(N, P-1)) % mod;}  //jou(n,mod-2)で逆元
//intの最大値2147483647 ≒ 2×10^9
//long longの最大値9223372036854775807 ≒ 9×10^18
//'大文字'+=32;    で小文字に
//  cout << fixed << setprecision (20);   小数点以下2０桁まで
//実行時間制約2秒では２×10^8回くらいまで計算できる




int main() {
    int h,w,a,b;
    cin >> h>>w>>a>>b;

  rep(i,b){
    rep(j,a) cout << 0;
    rep(j,w-a) cout << 1;
    cout << endl;
  }
  rep(i,h-b){
    rep(j,a) cout << 1;
    rep(j,w-a) cout << 0;
    cout << endl;
  }

}
