swhlab/common.py
def abfGroupFiles(groups,folder):
    """
    when given a dictionary where every key contains a list of IDs, replace
    the keys with the list of files matching those IDs. This is how you get a
    list of files belonging to each child for each parent.
    """
    assert os.path.exists(folder)
    files=os.listdir(folder)
    group2={}
    for parent in groups.keys():
        if not parent in group2.keys():
            group2[parent]=[]
        for ID in groups[parent]:
            for fname in [x.lower() for x in files if ID in x.lower()]:
                group2[parent].extend([fname])
    return group2
def abfGroupFiles(groups,folder):
    """
    when given a dictionary where every key contains a list of IDs, replace
    the keys with the list of files matching those IDs. This is how you get a
    list of files belonging to each child for each parent.
    """
    assert os.path.exists(folder)
    files=os.listdir(folder)
    group2={}
    for parent in groups.keys():
        if not parent in group2.keys():
            group2[parent]=[]
        for ID in groups[parent]:
            for fname in [x.lower() for x in files if ID in x.lower()]:
                group2[parent].extend([fname])
    return group2
def abfGroupFiles ( groups , folder ) : assert os . path . exists ( folder ) files = os . listdir ( folder ) group2 = { } for parent in groups . keys ( ) : if not parent in group2 . keys ( ) : group2 [ parent ] = [ ] for ID in groups [ parent ] : for fname in [ x . lower ( ) for x in files if ID in x . lower ( ) ] : group2 [ parent ] . extend ( [ fname ] ) return group2
when given a dictionary where every key contains a list of IDs, replace
    the keys with the list of files matching those IDs. This is how you get a
    list of files belonging to each child for each parent.
when given a dictionary where every key contains a list of IDs replace the keys with the list of files matching those IDs . This is how you get a list of files belonging to each child for each parent .