The hands of a circular clock form aangle at $$6:15$$ P.M. 
Overseas Competition->Knowledge Point->Distance Word Problems->Clock Problems
At $$6:15$$, hr. hand has moved $$\left(1/4\right)\times 30^{}\circ$$ from $$6$$, so $$\angle =90^{}\circ+30^{}\circ/4=97.5^{}\circ$$. 