Calculate: $${{2}^{2}}\div {{2}^{3}}\times {{2}^{4}}\div {{2}^{5}}\times {{2}^{6}}\div \cdots \div {{2}^{99}}\times {{2}^{100}}=$$~\uline{~~~~~~~~~~}~. 
Overseas Competition->Knowledge Point->Calculation Modules->Power->Computing Powers->Exponentiation of Powers
$$({{2}^{100}}\div {{2}^{99}})\times ({{2}^{98}}\div {{2}^{97}})\times \cdot \cdot \cdot \times ({{2}^{6}}\div {{2}^{5}})\times ({{2}^{4}}\div {{2}^{3}})\times {{2}^{2}}={{2}^{51}}$$ 