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Teacher wrote $$10$$ non-zero natural numbers in sequence on the blackboard, where the $$1$$st number is $$16$$, and the sum of any $$3$$ adjacent numbers is $$100$$. The biggest possibility of the $$8$$th number is~\uline{~~~~~~~~~~}~. 
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Let first 10 numbers be $${{a}\_{1}}$$、$${{a}\_{2}}$$、$${{a}\_{3}}$$、$${{a}\_{4}}$$、$$\ldots \ldots $$、$${{a}\_{10}}$$.  $${{a}\_{1}}+{{a}\_{2}}+{{a}\_{3}}={{a}\_{2}}+{{a}\_{3}}+{{a}\_{4}}$$，$${{a}\_{1}}={{a}\_{4}}$$.  Therefore, $${{a}\_{1}}={{a}\_{4}}={{a}\_{7}}={{a}\_{10}}=16$$，$${{a}\_{8}}=100-{{a}\_{10}}-{{a}\_{9}}=100-16-{{a}\_{9}}=84-{{a}\_{9}}$$.  The maximum value of $${{a}\_{8}}$$ is $$83$$. For example：$$16$$、$$83$$、$$1$$、$$16$$、$$83$$、$$1$$、$$16$$、$$83$$、$$1$$、$$16$$． 