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The solution to the rational equation $$\frac{16}{4-{{x}^{2}}}+\frac{x-2}{x+2}=\frac{x+2}{x-2}$$ is~\uline{~~~~~~~~~~}~. 
Overseas Competition->Knowledge Point->Calculation Modules
$$\begin{eqnarray}\frac{16}{4-{{x}^{2}}}+\frac{x-2}{x+2}\&=\&\frac{x+2}{x-2}\textbackslash\textbackslash{} -16+{{(x-2)}^{2}}\&=\&{{(x+2)}^{2}}\textbackslash\textbackslash{} x\&=\&-2\end{eqnarray}$$  After verification, $$x=-2$$ is not a solution.  There is no solution. 