Teacher Ying bought some sweets and divided them equally among $$9$$ children. If everyone got $$6$$ sweets, there would still be some sweets remaining. What is the most number of sweets Teacher Ying could have bought? What is the least amount of sweets Teacher Ying could have bought? 
Overseas Competition->Knowledge Point->Calculation Modules->Whole Numbers->Whole Numbers Multiplication and Division->Division of Whole Numbers->Division with Remainders
$$(\textbackslash{} \textbackslash{} \textbackslash{} \textbackslash{} )\div 9=6 R (\textbackslash{} \textbackslash{} \textbackslash{} \textbackslash{} )$$  Largest remainder: $$8$$, $$9\times 6+8=62$$  Smallest remainder: $$1$$, $$9\times 6+1=55$$ 